OK...let's see if any of you can solve this ...correctly....

You are making a 2 mile drive from point a to point c... passing through point b, which is exactly 1 mile from points a and c... the first leg from point a to point b is 1 mile, and uphill.... the second leg from point b to point c is 1 mile, downhill

For the purpose of this problem, we will assume instantaneous acceleration and deceleration..

You drive exactly 30mph on the first leg (point a to b)

How fast would you have to drive on the second leg (point b to point c) in order to average 60mph for the entire trip?

I will give everyone 24 hours to solve it....then I'll post the answer in comments.... HINT: it ain't as easy as you think.....

Copy & paste to friend:(Click inside box; Ctrl + C to copy; Ctrl + V to paste)

The correct answer is.....YOU CAN"T AVERAGE 60MPH FOR THE TRIP !!!

REASONING:.....If you averaged 60mph for the entire trip, it would have taken you 2 minutes to complete it...

.....Since you only drove 30mph on the first leg, that alone took you 2 minutes.

......Therefore, no matter how fast you drive the second leg, you will always average something less than 60mph.

People tend to forget about the TIME element ..And this is an ACTUAL question I ask Professional drivers during job interviews...They are given 10 minutes to figure it out...Very few get it right.....